Physics Circle home Student Login

Home›Chapters›Motion in One Dimension PYQs›Equations of Kinematics›Question 20

JEE Main 2022 (30 Jul, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2022 (30 Jul, Shift 2)

Q20JEE Main 2022 · 30 JUL · SHIFT 2Easy

Equations of Kinematics

Two trucks A and B are approaching each other on a straight path with the velocities of 16 m/s16\text{ m/s} and 20 m/s20\text{ m/s} respectively. When they are 200 m200\text{ m} apart their drivers see each other and applies the breaks simultaneously. If the truck A decelerates with 2 m/s22\text{ m/s}^2 and truck B decelerates with 4 m/s24\text{ m/s}^2, what is the distance between them when they finally stop?

Show answer and solution

Answer: (c)

  1. Stopping distance s=u22as = \frac{u^2}{2a} for each truck.
  2. Truck A: sA=1622×2=64 ms_A = \frac{16^2}{2 \times 2} = 64\text{ m}; truck B: sB=2022×4=50 ms_B = \frac{20^2}{2 \times 4} = 50\text{ m}.
  3. Gap left =200−(64+50)=86 m= 200 - (64 + 50) = 86\text{ m}.
  4. So the answer is (c) 86 m86\text{ m}.
Report a mistake

More questions on Equations of Kinematics