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MHT CET 2025 (25 Apr, Shift 1) · Beats

Beats question from MHT CET 2025 (25 Apr, Shift 1)

Q15MHT CET 2025 · 25 APR · SHIFT 1Easy

Beats

Two tuning forks of frequencies 256 Hz and 258 Hz are sounded together. The time interval between two consecutive maxima is

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Answer: (d)

  1. Beat frequency =258−256=2 Hz= 258 - 256 = 2\text{ Hz}
  2. Time between consecutive maxima =12 s=0.5 s= \frac{1}{2}\text{ s} = 0.5\text{ s}
  3. So the answer is (d) 0.5 s.
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