Two tuning forks of frequencies 320 Hz and 480 Hz are sounded together to produce sound waves. The velocity of sound in air is 320 ms⁻¹. The difference between wavelengths of these waves is nearly (a) 48 cm (b) 16.5 cm (c) 33 cm (d) 42 cm

Answer: (c). λ = v/n for each fork. λ₁ = (320)/(320) = 1 m, λ₂ = (320)/(480) = 0.667 m Δλ = 1 - 0.667 = 0.333 m ≈ 33 cm So the answer is (c) 33 cm.

Two tuning forks of frequencies 320 Hz and 480 Hz are sounded… | MHT CET 2021 (24 Sep, Shift 1)

Q25MHT CET 2021 · 24 SEP · SHIFT 1Easy

Wave Basics & Properties of Sound

Two tuning forks of frequencies $320\text{ Hz}$ and $480\text{ Hz}$ are sounded together to produce sound waves. The velocity of sound in air is $320\text{ ms}^{-1}$ . The difference between wavelengths of these waves is nearly

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Answer: (c)

$\lambda = \frac{v}{n}$ for each fork.
$\lambda_1 = \frac{320}{320} = 1$ m, $\lambda_2 = \frac{320}{480} = 0.667$ m
$\Delta\lambda = 1 - 0.667 = 0.333$ m $\approx 33$ cm
So the answer is (c) 33 cm.

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Wave Basics & Properties of Sound question from MHT CET 2021 (24 Sep, Shift 1)

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