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MHT CET 2025 (23 Apr, Shift 1) · Beats

Beats question from MHT CET 2025 (23 Apr, Shift 1)

Q21MHT CET 2025 · 23 APR · SHIFT 1Medium

Beats

Two tuning forks when sounded together produce 4 beats per second. One of the forks is in unison with 23 cm length of sonometer wire and other with 24 cm length of the same wire. The frequencies of the two tuning forks are

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Answer: (a)

  1. f∝1Lf \propto \dfrac{1}{L}: f1×23=f2×24f_1 \times 23 = f_2 \times 24, with f1−f2=4f_1 - f_2 = 4.
  2. f2(2423−1)=4⇒f2=92 Hzf_2\left(\dfrac{24}{23} - 1\right) = 4 \Rightarrow f_2 = 92\text{ Hz}
  3. f1=96 Hzf_1 = 96\text{ Hz}
  4. So the answer is (a) 96 Hz, 92 Hz.
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