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JEE Main 2022 (26 Jul, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2022 (26 Jul, Shift 2)

Q73JEE Main 2022 · 26 JUL · SHIFT 2Medium

Electric Potential & Equipotentials

Two uniformly charged spherical conductors AA and BB of radii 5 mm5\text{ mm} and 10 mm10\text{ mm} are separated by a distance of 2 cm2\text{ cm}. If the spheres are connected by a conducting wire, then in equilibrium condition, the ratio of the magnitudes of the electric fields at the surface of the sphere AA and BB will be:

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Answer: (b)

  1. Connected spheres are at equal potential, so E=Vr∝1rE = \frac{V}{r} \propto \frac{1}{r} (separation is large compared with radii).
  2. EAEB=rBrA=105=2\frac{E_A}{E_B} = \frac{r_B}{r_A} = \frac{10}{5} = 2
  3. So the answer is (b) 2:12 : 1.
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