Two vibrating tuning forks produce progressive waves given by y₁ = 4sin 500π t and y₂ = 2sin 506π t. Number of beats produced per minute is (a) 360 (b) 180 (c) 120 (d) 30

Answer: (b). f₁ = (500π)/(2π) = 250 Hz, f₂ = (506π)/(2π) = 253 Hz Beats = 3 per second = 3 × 60 = 180 per minute So the answer is (b) 180.

Two vibrating tuning forks produce progressive waves given by y₁ =… | NEET 2005 (AIPMT)

Q70NEET 2005 · AIPMTEasy

Beats

Two vibrating tuning forks produce progressive waves given by $y_1 = 4\sin 500\pi t$ and $y_2 = 2\sin 506\pi t$ . Number of beats produced per minute is

Show answer and solution

Answer: (b)

$f_1 = \frac{500\pi}{2\pi} = 250\text{ Hz}$ , $f_2 = \frac{506\pi}{2\pi} = 253\text{ Hz}$
Beats $= 3$ per second $= 3 \times 60 = 180$ per minute
So the answer is (b) 180.

Report a mistake

Beats question from NEET 2005 (AIPMT)

More questions on Beats