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JEE Main 2025 (2 Apr, Shift 2) · Splitting & Merging of Drops

Splitting & Merging of Drops question from JEE Main 2025 (2 Apr, Shift 2)

Q22JEE Main 2025 · 2 APR · SHIFT 2Medium

Splitting & Merging of Drops

Two water drops each of radius ' rr ' coalesce to form a bigger drop. If ' TT ' is the surface tension, the surface energy released in this process is:

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Answer: (c)

  1. R=21/3rR = 2^{1/3} r (volume conserved).
  2. Energy released =T(2⋅4πr2−4π22/3r2)= T\left(2 \cdot 4\pi r^2 - 4\pi 2^{2/3} r^2\right)
  3. =4πr2T[2−22/3]= 4\pi r^2 T\left[2 - 2^{2/3}\right]
  4. So the answer is (c).
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