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MHT CET 2022 (11 Aug, Shift 2) · Reflection, Superposition & Interference

Reflection, Superposition & Interference question from MHT CET 2022 (11 Aug, Shift 2)

Q14MHT CET 2022 · 11 AUG · SHIFT 2Easy

Reflection, Superposition & Interference

Two waves are superimposed whose ratio of intensities is $9 : 1$ . The ratio of maximum and minimum intensity is

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Answer: (b)

$I \propto a^2$ , so $\frac{a_1}{a_2} = \sqrt{\frac{9}{1}} = 3$ .
$\frac{I_{max}}{I_{min}} = \left(\frac{a_1 + a_2}{a_1 - a_2}\right)^2 = \left(\frac{3 + 1}{3 - 1}\right)^2 = 4$ .
So the answer is (b) $4 : 1$ .

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