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NEET 2001 (AIPMT) · Reflection, Superposition & Interference

Reflection, Superposition & Interference question from NEET 2001 (AIPMT)

Q21NEET 2001 · AIPMTEasy

Reflection, Superposition & Interference

Two waves having equation x1 = $a$ sin( $\omega$ t $-$ kx + $\phi$ 1), x2 = asin( $\omega$ t $-$ kx + $\phi$ 2). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is

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Answer: (b)

$A_R^2 = 2a^2(1 + \cos\phi)$ where $\phi = \phi_1 - \phi_2$
$A_R = a \Rightarrow 1 + \cos\phi = \frac{1}{2} \Rightarrow \cos\phi = -\frac{1}{2}$
$\phi = \frac{2\pi}{3}$
So the answer is (b) $\frac{2\pi}{3}$ .

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