Student Login

Home›Chapters›Wave Motion PYQs›Stationary Waves & Vibrating Strings›Question 4

MHT CET 2026 (19 Apr, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2026 (19 Apr, Shift 2)

Q4MHT CET 2026 · 19 APR · SHIFT 2Easy

Stationary Waves & Vibrating Strings

Two waves of same frequency ( $n$ ) approaching each other with same velocity of $18$ m/s interfere. The distance between two consecutive antinodes is

Show answer and solution

Answer: (c)

$\lambda = \frac{v}{n} = \frac{18}{n}$ .
Consecutive antinodes are $\frac{\lambda}{2} = \frac{9}{n}$ apart.
So the answer is (c) $\frac{9}{n}$ .

Report a mistake

More questions on Stationary Waves & Vibrating Strings

In case of stationary wave pattern, which of the following statement is CORRECT?MHT CET 2026 (17 Apr, Shift 1)
In a stationary wave, all the particlesMHT CET 2026 (13 Apr, Shift 1)
A stretched string of length ' L ' is fixed at both the ends, has ' n ' nodes ( n > 2)…MHT CET 2026 (19 May, Shift 1)
The fundamental frequency ' n ' of the tuning fork is 288 Hz, it will not resonate with…MHT CET 2026 (18 Apr, Shift 2)
When a sonometer wire vibrates in the third overtone, the number of antinodes and nodes…MHT CET 2026 (16 Apr, Shift 1)
A sonometer wire is vibrating in third overtone. There areMHT CET 2026 (13 Apr, Shift 1)
A uniform wire of length L, diameter D and density ρ is stretched under tension T. The…MHT CET 2026 (15 May, Shift 1)
To increase the frequency of transverse oscillations of a stretched string by 40%, the…MHT CET 2026 (15 Apr, Shift 2)