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MHT CET 2026 (16 Apr, Shift 2) · Beats

Beats question from MHT CET 2026 (16 Apr, Shift 2)

Q4MHT CET 2026 · 16 APR · SHIFT 2Easy

Beats

Two waves $Y_1 = 0.25\sin 316t$ and $Y_2 = 0.25\sin 310t$ are propagating along the same direction. The number of beats produced per second are

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Answer: (a)

$f = \frac{\omega}{2\pi}$ , so beat frequency $= \frac{\omega_1 - \omega_2}{2\pi}$
$= \frac{316 - 310}{2\pi} = \frac{6}{2\pi} = \frac{3}{\pi}$ per second
So the answer is (a) $\frac{3}{\pi}$ .

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