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JEE Main 2023 (10 Apr, Shift 1) · Wire Combinations & Special Cases

Wire Combinations & Special Cases question from JEE Main 2023 (10 Apr, Shift 1)

Q10JEE Main 2023 · 10 APR · SHIFT 1Medium

Wire Combinations & Special Cases

Two wires each of radius 0.2 cm and negligible mass, one made of steel and the other made of brass are loaded as shown in the figure. The elongation of the steel wire is __________ ×\times 10 −6{}^{-6} m. [Young's modulus for steel = 2 ×\times 1011{}^{11} Nm−2{}^{-2} and g = 10 ms−2{}^{-2} ]

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 20

  1. Steel wire holds both blocks: T=(2+1.14)×10=31.4 NT = (2 + 1.14) \times 10 = 31.4\text{ N}
  2. A=π(0.2×10−2)2=1.256×10−5 m2A = \pi (0.2 \times 10^{-2})^2 = 1.256 \times 10^{-5}\text{ m}^2
  3. Δl=TLAY=31.4×1.61.256×10−5×2×1011=2×10−5 m\Delta l = \frac{TL}{AY} = \frac{31.4 \times 1.6}{1.256 \times 10^{-5} \times 2 \times 10^{11}} = 2 \times 10^{-5}\text{ m}
  4. Elongation =20×10−6 m= 20 \times 10^{-6}\text{ m}
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