Elastic Behaviour, Stress & Strain question from MHT CET 2020 (16 Oct, Shift 2)

Answer: (c)

1. In series the same force $F$ acts through both wires, and both have the same area $\frac{\pi d^2}{4}$.
2. Stress $= \frac{F}{A}$ is therefore the same in both.
3. Strain $= \frac{\text{stress}}{Y}$ differs because the materials have different $Y$.
4. So the answer is (c) same stress but different strain.