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MHT CET 2026 (17 Apr, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2026 (17 Apr, Shift 2)

Q8MHT CET 2026 · 17 APR · SHIFT 2Medium

Current Loop as a Magnetic Dipole

Two wires of same length are bent to form the circular loop with two turns and a square loop of one turn. Both of them carry same current. The ratio of magnetic moment of circular loop of two turns to that of square loop is

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Answer: (d)

  1. Wire length LL, current II.
  2. Circle, 2 turns: 2(2πr)=L⇒r=L4π2(2\pi r) = L \Rightarrow r = \frac{L}{4\pi}; Mc=2Iπr2=IL28πM_c = 2I\pi r^2 = \frac{IL^2}{8\pi}.
  3. Square, 1 turn: side L4\frac{L}{4}; Ms=IL216M_s = \frac{IL^2}{16}.
  4. McMs=168π=2π\frac{M_c}{M_s} = \frac{16}{8\pi} = \frac{2}{\pi}, so the answer is (d) 2:π2 : \pi.
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