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NEET 1995 (AIPMT) · Combination of Resistors

Combination of Resistors question from NEET 1995 (AIPMT)

Q82NEET 1995 · AIPMTEasy

Combination of Resistors

Two wires of the same metal have same length, but their cross-sections are in the ratio $3 : 1$ . They are joined in series. The resistance of thicker wire is $10\ \Omega$ . The total resistance of the combination will be

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Answer: (a)

Same metal and length, so $R \propto 1/A$ .
Thicker wire $10\ \Omega$ ; thinner (area $1/3$ ) has $30\ \Omega$ .
Series: $10 + 30 = 40\ \Omega$ . The answer is (a).

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