Capacitors in DC Circuits & RC question from JEE Main 2026 (5 Apr, Shift 2)

Answer: (a)

1. In steady state the capacitor branch carries no current, so current flows through $6\ \Omega$ and $2\ \Omega$ only.
2. $I = \dfrac{2}{6+2} = 0.25\text{ A}$
3. The capacitor branch is across the $2\ \Omega$ resistor, and no current flows in its $4\ \Omega$: $V_C = 0.25\times2 = 0.5\text{ V}$
4. So the answer is (a) 0.5 V.