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JEE Main 2025 (7 Apr, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from JEE Main 2025 (7 Apr, Shift 1)

Q25JEE Main 2025 · 7 APR · SHIFT 1Difficult

Moving Charge in a Magnetic Field

Uniform magnetic fields of different strengths (B1(B_1 and B2)B_2), both normal to the plane of the paper exist as shown in the figure. A charged particle of mass mm and charge qq, at the interface at an instant, moves into the region 2 with velocity vv and returns to the interface. It continues to move into region 1 and finally reaches the interface. What is the displacement of the particle during this movement along the interface?

Figure

(Consider the velocity of the particle to be normal to the magnetic field and B2>B1B_2 > B_1)

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Answer: (a)

Region 1 (B1)Region 2 (B2)startendr2r12(r1 - r2)
  1. Radii: r1=mvqB1r_1 = \dfrac{mv}{qB_1}, r2=mvqB2r_2 = \dfrac{mv}{qB_2}, with r2<r1r_2 < r_1 since B2>B1B_2 > B_1.
  2. In region 2 the particle makes a semicircle and returns to the interface shifted by 2r22r_2 in one direction.
  3. Both fields point the same way, so the sense of rotation is the same; in region 1 it makes a semicircle that shifts it by 2r12r_1 in the opposite direction.
  4. Net displacement =2(r1−r2)=2mvqB1(1−B1B2)= 2(r_1 - r_2) = \dfrac{2mv}{qB_1}\left(1 - \dfrac{B_1}{B_2}\right)
  5. So the answer is (a).
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