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MHT CET 2025 (25 Apr, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2025 (25 Apr, Shift 2)

Q15MHT CET 2025 · 25 APR · SHIFT 2Medium

Rotational Kinetic Energy, Work & Power

Using Bohr's quantisation condition, what is the rotational energy in the second orbit for a diatomic molecule?

( I=I = moment of inertia of diatomic molecule and h=h = Planck's constant)

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Answer: (b)

  1. Bohr condition: L=nh2πL = \frac{nh}{2\pi}; for n=2n = 2, L=hπL = \frac{h}{\pi}
  2. E=L22I=h22Iπ2E = \frac{L^2}{2I} = \frac{h^2}{2I\pi^2}
  3. So the answer is (b) h22Iπ2\frac{h^2}{2I\pi^2}.
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