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MHT CET 2024 (9 May, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (9 May, Shift 2)

Q32MHT CET 2024 · 9 MAY · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Using Einstein's photoelectric equation, the graph between kinetic energy of emitted photoelectrons and the frequency of incident radiation is shown correctly by graph

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Answer: (a)

$E = h\nu - \phi$ : a straight line with positive slope $h$ .
$E = 0$ at $\nu = \nu_0$ , and no electrons are emitted below $\nu_0$ , so the line starts from a point on the $\nu$ axis.
Graph 1 shows this.
So the answer is (a) 1.

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