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JEE Main 2025 (23 Jan, Shift 2) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from JEE Main 2025 (23 Jan, Shift 2)

Q20JEE Main 2025 · 23 JAN · SHIFT 2Medium

P-V Diagrams & Cyclic Processes

Figure

Using the given P−VP - V diagram, the work done by an ideal gas along the path ABCDABCD is:

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Answer: (b)

  1. A→BA \to B (isobaric, P0P_0): W=P0(3V0−2V0)=P0V0W = P_0(3V_0 - 2V_0) = P_0V_0.
  2. B→CB \to C (isochoric): W=0W = 0.
  3. C→DC \to D (isobaric, 2P02P_0): W=2P0(V0−3V0)=−4P0V0W = 2P_0(V_0 - 3V_0) = -4P_0V_0.
  4. Total W=P0V0−4P0V0=−3P0V0W = P_0V_0 - 4P_0V_0 = -3P_0V_0
  5. So the answer is (b) −3P0V0-3P_0V_0.
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