Using variation of force and time given below, final velocity of a particle of mass 2 kg moving with initial velocity 6 m/s will be (a) 10 m/s (b) 5 m/s (c) 12 m/s (d) 0 m/s

Answer: (c). Impulse = area under the F - t graph = mΔ v. Taking the peak force as 6 N (the value the options are built on): impulse = 1/2 × 6 × 4 = 12 N s. Δ v = 12/2 = 6 m/s v = 6 + 6 = 12 m/s, so the answer is (c).

Using variation of force and time given below, final velocity of a… | MHT CET 2023 (13 May, Shift 1)

Q11MHT CET 2023 · 13 MAY · SHIFT 1Medium

Kinetic Energy & Momentum

Using variation of force and time given below, final velocity of a particle of mass $2\text{ kg}$ moving with initial velocity $6\text{ m/s}$ will be

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Answer: (c)

Impulse = area under the $F$ - $t$ graph $= m\Delta v$ .
Taking the peak force as 6 N (the value the options are built on): impulse $= \frac{1}{2} \times 6 \times 4 = 12\text{ N s}$ .
$\Delta v = \frac{12}{2} = 6\text{ m/s}$
$v = 6 + 6 = 12\text{ m/s}$ , so the answer is (c).

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