Vector A of magnitude 5√(3) units, another vector B of magnitude of 10 units are inclined to each other at an angle of 30°. The magnitude of vector product of the two vectors is [sin 30° = 1/2] (a) 5√(3) units (b) 10 units (c) 25√(3) units (d) 75 units

Answer: (c). |A × B| = ABsin θ = 5√(3) × 10 × 1/2 = 25√(3) units So the answer is (c).

Vector A of magnitude 5√(3) units, another vector B of magnitude of… | MHT CET 2025 (25 Apr, Shift 1)

Q5MHT CET 2025 · 25 APR · SHIFT 1Easy

Vector (Cross) Product

Vector $\vec{A}$ of magnitude $5\sqrt{3}$ units, another vector $\vec{B}$ of magnitude of 10 units are inclined to each other at an angle of $30^\circ$ . The magnitude of vector product of the two vectors is $\left[\sin 30^\circ = \frac{1}{2}\right]$

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Answer: (c)

$|\vec{A} \times \vec{B}| = AB\sin\theta$
$= 5\sqrt{3} \times 10 \times \frac{1}{2} = 25\sqrt{3}$ units
So the answer is (c).

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Vector (Cross) Product question from MHT CET 2025 (25 Apr, Shift 1)

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