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MHT CET 2024 (15 May, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2024 (15 May, Shift 2)

Q39MHT CET 2024 · 15 MAY · SHIFT 2Easy

Progressive Wave Equation

Velocity of sound waves in air is $330\text{ m/s}$ . For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of $1.6\pi$ . frequency of this wave is

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Answer: (c)

$\Delta\phi = \frac{2\pi}{\lambda}\Delta x \Rightarrow 1.6\pi = \frac{2\pi \times 0.4}{\lambda}$
$\lambda = \frac{0.8}{1.6} = 0.5$ m
$f = \frac{v}{\lambda} = \frac{330}{0.5} = 660$ Hz
So the answer is (c) 660 Hz.

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