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MHT CET 2024 (2 May, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2024 (2 May, Shift 1)

Q46MHT CET 2024 · 2 MAY · SHIFT 1Easy

Progressive Wave Equation

Velocity of sound waves in air is 330 m/s330\text{ m/s}. For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of 1.6π1.6\pi. The frequency of this wave is

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Answer: (c)

  1. Δϕ=2πλΔx⇒1.6π=2π×0.4λ\Delta\phi = \frac{2\pi}{\lambda}\Delta x \Rightarrow 1.6\pi = \frac{2\pi \times 0.4}{\lambda}, so λ=0.5\lambda = 0.5 m.
  2. f=vλ=3300.5=660f = \frac{v}{\lambda} = \frac{330}{0.5} = 660 Hz
  3. So the answer is (c) 660 Hz.
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