Velocity of sound waves in air is 330 m/s. For a particular sound wave in air, a path difference of 40 cm is equivalent to phase difference of 1.6π. The frequency of this wave is (a) 165 Hz (b) 150 Hz (c) 660 Hz (d) 330 Hz

Answer: (c). Δφ = (2π)/(λ)Δ x ⇒ 1.6π = (2π(0.4))/(λ) λ = (0.8)/(1.6) = 0.5 m f = (v)/(λ) = (330)/(0.5) = 660 Hz So the answer is (c) 660 Hz.

Velocity of sound waves in air is 330 m/s. For a particular sound… | NEET 1990 (AIPMT)

Q108NEET 1990 · AIPMTEasy

Progressive Wave Equation

Velocity of sound waves in air is $330\text{ m/s}$ . For a particular sound wave in air, a path difference of $40\text{ cm}$ is equivalent to phase difference of $1.6\pi$ . The frequency of this wave is

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Answer: (c)

$\Delta\phi = \frac{2\pi}{\lambda}\Delta x \Rightarrow 1.6\pi = \frac{2\pi(0.4)}{\lambda}$
$\lambda = \frac{0.8}{1.6} = 0.5\text{ m}$
$f = \frac{v}{\lambda} = \frac{330}{0.5} = 660\text{ Hz}$
So the answer is (c) $660\text{ Hz}$ .

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Progressive Wave Equation question from NEET 1990 (AIPMT)

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