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MHT CET 2025 (21 Apr, Shift 2) · Types of Flow, Reynolds Number & Continuity

Types of Flow, Reynolds Number & Continuity question from MHT CET 2025 (21 Apr, Shift 2)

Q6MHT CET 2025 · 21 APR · SHIFT 2Easy

Types of Flow, Reynolds Number & Continuity

Water flows through a horizontal pipe of varying cross-section at the rate of π×10−1 m3/s\pi \times 10^{-1}\text{ m}^3/\text{s}. The velocity of water at a point where the radius of the pipe is 10 cm is (π=3.14)(\pi = 3.14)

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Answer: (c)

  1. Rate of flow Q=Av=πr2vQ = Av = \pi r^2 v.
  2. v=π×10−1π(0.1)2=10−110−2=10 m/sv = \dfrac{\pi \times 10^{-1}}{\pi (0.1)^2} = \dfrac{10^{-1}}{10^{-2}} = 10\text{ m/s}
  3. So the answer is (c) 10 m/s10\text{ m/s}.
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