Water from a tap emerges vertically downwards with an initial speed… | JEE Main 2019 (10 Apr, Shift 2)

Q19JEE Main 2019 · 10 APR · SHIFT 2Medium

Types of Flow, Reynolds Number & Continuity

Water from a tap emerges vertically downwards with an initial speed of 1.0 ms–1. The cross- sectional area of the tap is 10–4 m2. Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross-sectional area of the stream, 0.15 m below the tap would be: (Take g = 10 ms–2)

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Answer: (c)

Speed after falling $h$ : $v^2 = u^2 + 2gh = 1 + 2\times10\times0.15 = 4 \Rightarrow v = 2\text{ m/s}$
Continuity: $A_1 u = A_2 v \Rightarrow A_2 = \dfrac{10^{-4}\times1}{2}$
$A_2 = 5\times10^{-5}\text{ m}^2$
So the answer is (c).

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