Water is flowing in a conical tube as shown in figure. Velocity of water at area ' A₂ ' is 60 cm/s. The value of ' A₁ ' and ' A₂ ' is 10 cm² and 5 cm² respectively. The pressure difference at both the cross- section is (a) 230 N/m² (b) 200 N/m² (c) 135 N/m² (d) 105 N/m²

Answer: (c). Continuity: v₁ = (A₂ v₂)/(A₁) = (5×0.6)/(10) = 0.3 m/s Bernoulli (horizontal): P₁ - P₂ = 1/2ρ (v₂² - v₁²) = 1/2×1000×(0.36 - 0.09) P₁ - P₂ = 500 × 0.27 = 135 N/m² So the answer is (c).

Water is flowing in a conical tube as shown in figure. Velocity of… | MHT CET 2024 (9 May, Shift 1)

Q12MHT CET 2024 · 9 MAY · SHIFT 1Medium

Bernoulli's Equation

Water is flowing in a conical tube as shown in figure. Velocity of water at area ' $A_2$ ' is $60\text{ cm/s}$ . The value of ' $A_1$ ' and ' $A_2$ ' is $10\text{ cm}^2$ and $5\text{ cm}^2$ respectively. The pressure difference at both the cross- section is

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Answer: (c)

Continuity: $v_1 = \dfrac{A_2 v_2}{A_1} = \dfrac{5\times0.6}{10} = 0.3\text{ m/s}$
Bernoulli (horizontal): $P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2) = \frac{1}{2}\times1000\times(0.36 - 0.09)$
$P_1 - P_2 = 500 \times 0.27 = 135\text{ N/m}^2$
So the answer is (c).

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