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MHT CET 2026 (20 May, Shift 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2026 (20 May, Shift 1)

Q2MHT CET 2026 · 20 MAY · SHIFT 1Easy

Angle of Contact & Capillarity

Water rises to a height of $2.2$ cm in glass capillary tube. The height to which water will rise in another capillary having one-fourth area of cross-section as that of the first is.

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Answer: (b)

$h \propto \frac{1}{r}$ and area $A = \pi r^2$ , so $h \propto \frac{1}{\sqrt{A}}$ .
$A' = \frac{A}{4} \Rightarrow r' = \frac{r}{2} \Rightarrow h' = 2h$
$h' = 2 \times 2.2 = 4.4\text{ cm}$
So the answer is (b) $4.4\text{ cm}$ .

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