Water rises to a height of 2 cm in a capillary tube. If cross-sectional area of the tube is reduced to 1/16 th of initial area then water will rise to a height of (a) 4 cm (b) 8 cm (c) 12 cm (d) 16 cm

Answer: (b). h ∝ 1/r ∝ 1/√(A) A' = A/16 ⇒ r' = r/4 ⇒ h' = 4h = 8 cm So the answer is (b) 8 cm.

Water rises to a height of 2 cm in a capillary tube. If… | MHT CET 2021 (23 Sep, Shift 1)

Q47MHT CET 2021 · 23 SEP · SHIFT 1Easy

Angle of Contact & Capillarity

Water rises to a height of $2\text{ cm}$ in a capillary tube. If cross-sectional area of the tube is reduced to $\frac{1}{16}$ th of initial area then water will rise to a height of

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Answer: (b)

$h \propto \frac{1}{r} \propto \frac{1}{\sqrt{A}}$
$A' = \frac{A}{16} \Rightarrow r' = \frac{r}{4} \Rightarrow h' = 4h = 8\text{ cm}$
So the answer is (b) $8$ cm.

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