Water rises up to a height h in a capillary tube on the surface of the earth. The value of h will increase, if the experimental set up is kept in ( g = acceleration due to gravity) (a) a lift going upward with a certain acceleration (b) accelerating train (c) a satellite rotating close to earth (d) a lift going down with acceleration less than ' g '

Answer: (d). h = 2Tcos θrρ geff ∝ 1geff Lift going up: geff = g + a, h decreases. Lift going down with a < g: geff = g - a, h increases. So the answer is (d).

Water rises up to a height h in a capillary tube on the surface of… | MHT CET 2026 (14 May, Shift 1)

Q3MHT CET 2026 · 14 MAY · SHIFT 1Easy

Angle of Contact & Capillarity

Water rises up to a height $h$ in a capillary tube on the surface of the earth. The value of $h$ will increase, if the experimental set up is kept in ( $g$ = acceleration due to gravity)

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Answer: (d)

$h = \frac{2T\cos\theta}{r\rho g_{eff}} \propto \frac{1}{g_{eff}}$
Lift going up: $g_{eff} = g + a$ , $h$ decreases. Lift going down with $a < g$ : $g_{eff} = g - a$ , $h$ increases.
So the answer is (d).

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Angle of Contact & Capillarity question from MHT CET 2026 (14 May, Shift 1)

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