Wavelengths of light used in an optical instrument are λ₁ = 4000 Å and λ₂ = 5000 Å, then ratio of their respective resolving powers (corresponding to λ₁ and λ₂) is: (a) 16: 25 (b) 9: 1 (c) 4: 5 (d) 5: 4

Answer: (d). Resolving power ∝ (1)/(λ). (RP₁)/(RP₂) = (λ₂)/(λ₁) = (5000)/(4000) = 5/4 So the answer is (d) 5:4.

Wavelengths of light used in an optical instrument are λ₁ = 4000 Å… | JEE Main 2002 (AIEEE)

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Resolving Power

Wavelengths of light used in an optical instrument are $\lambda_1 = 4000\text{ Å}$ and $\lambda_2 = 5000\text{ Å},$ then ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$ ) is:

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Answer: (d)

Resolving power $\propto \dfrac{1}{\lambda}$ .
$\dfrac{RP_1}{RP_2} = \dfrac{\lambda_2}{\lambda_1} = \dfrac{5000}{4000} = \dfrac{5}{4}$
So the answer is (d) $5:4$ .

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