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MHT CET 2026 (12 May, Shift 2) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2026 (12 May, Shift 2)

Q3MHT CET 2026 · 12 MAY · SHIFT 2Easy

Thermometry & Thermal Expansion

What is the change in volume of an iron sphere of volume 400400 cm3^3, when it is heated from 0∘C0^\circ\text{C} to 50∘C50^\circ\text{C}? (αiron=12×10−6/∘C\alpha_{\text{iron}} = 12 \times 10^{-6}/^\circ\text{C})

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Answer: (c)

  1. γ=3α=36×10−6/∘\gamma=3\alpha=36\times10^{-6}/^\circC, ΔV=VγΔT\Delta V=V\gamma\Delta T
  2. ΔV=400×36×10−6×50=0.72\Delta V=400\times 36\times10^{-6}\times 50=0.72 cm3^3
  3. So the answer is (c) 0.720.72 cm3^3.
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