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NEET 2020 (Phase 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from NEET 2020 (Phase 2)

Q102NEET 2020 · PHASE 2Easy

Acceleration Due to Gravity

What is the depth at which the value of acceleration due to gravity becomes $1/n$ times the value that at the surface of earth? (radius of earth $= R$ )

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Answer: (c)

At depth $d$ : $g_d = g\left(1 - \frac{d}{R}\right)$ .
$\frac{1}{n} = 1 - \frac{d}{R} \Rightarrow d = \frac{R(n-1)}{n}$
So the answer is (c).

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