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NEET 2020 (Phase 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from NEET 2020 (Phase 2)

Q102NEET 2020 · PHASE 2Easy

Acceleration Due to Gravity

What is the depth at which the value of acceleration due to gravity becomes 1/n1/n times the value that at the surface of earth? (radius of earth =R= R)

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Answer: (c)

  1. At depth dd: gd=g(1−dR)g_d = g\left(1 - \frac{d}{R}\right).
  2. 1n=1−dR⇒d=R(n−1)n\frac{1}{n} = 1 - \frac{d}{R} \Rightarrow d = \frac{R(n-1)}{n}
  3. So the answer is (c).
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