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JEE Main 2024 (5 Apr, Shift 2) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2024 (5 Apr, Shift 2)

Q19JEE Main 2024 · 5 APR · SHIFT 2Easy

Applications of Dimensional Analysis

What is the dimensional formula of ab−1ab^{-1} in the equation (P+aV2)(V−b)=RT\left(\mathrm{P} + \frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V} - \mathrm{b}) = \mathrm{RT}, where letters have their usual meaning.

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Answer: (d)

  1. [a]=[P][V2]=[ML−1T−2][L6]=[ML5T−2][a] = [P][V^2] = [ML^{-1}T^{-2}][L^6] = [ML^5T^{-2}]; [b]=[V]=[L3][b] = [V] = [L^3].
  2. [ab−1]=[ML5T−2]/[L3]=[ML2T−2][ab^{-1}] = [ML^5T^{-2}]/[L^3] = [ML^2T^{-2}].
  3. So the answer is (d).
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