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JEE Main 2025 (23 Jan, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from JEE Main 2025 (23 Jan, Shift 1)

Q10JEE Main 2025 · 23 JAN · SHIFT 1Easy

Refraction, Glass Slab & Apparent Depth

What is the lateral shift of a ray refracted through a parallel-sided glass slab of thickness ' $h$ ' in terms of the angle of incidence ' $i$ ' and angle of refraction ' $r$ ', if the glass slab is placed in air medium?

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Answer: (d)

Path inside the slab: $OB = \frac{h}{\cos r}$ .
Lateral shift = perpendicular distance between incident and emergent rays $= OB \sin(i - r)$
$d = \frac{h \sin(i-r)}{\cos r}$ . So the answer is (d).

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