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NEET 1995 (AIPMT) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from NEET 1995 (AIPMT)

Q45NEET 1995 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

What is the respective number of $\alpha$ and $\beta$ particles emitted in the following radioactive decay? ${}^{200}X_{90} \rightarrow {}^{168}Y_{80}$

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Answer: (b)

Here the mass number is 200 and atomic number 90, changing to 168 and 80.
$n_\alpha = \dfrac{200 - 168}{4} = 8$ ; after $8\alpha$ : $Z = 90 - 16 = 74$ .
$n_\beta = 80 - 74 = 6$
So the answer is (b) 8 and 6.

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