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NEET 1993 (AIPMT) · Self-Inductance & Energy

Self-Inductance & Energy question from NEET 1993 (AIPMT)

Q85NEET 1993 · AIPMTEasy

Self-Inductance & Energy

What is the self-inductance of a coil which produces 5 V when the current changes from 3 ampere to 2 ampere in one millisecond?

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Answer: (b)

  1. ∣e∣=LΔIΔt|e| = L\frac{\Delta I}{\Delta t} with ΔI=1 A\Delta I = 1\text{ A}, Δt=10−3 s\Delta t = 10^{-3}\text{ s}.
  2. 5=L×110−3⇒L=5×10−3 H5 = L \times \frac{1}{10^{-3}} \Rightarrow L = 5\times10^{-3}\text{ H}
  3. L=5 mHL = 5\text{ mH}, so the answer is (b).
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