What is the self inductance of a solenoid of length 10π cm, area of cross-section 10⁻³ m ² and total number of turns 10³? ( μ₀ = 4π × 10⁻⁷ SI unit) (a) 4 mH (b) 4 H (c) 40 H (d) 0.4 H

Answer: (a). L = (μ₀ N² A)/(l) with l = 10π cm = 0.1π m. L = 4π×10⁻⁷×10⁶×10⁻³0.1π L = 4×10⁻⁴0.1 = 4×10⁻³ H So the answer is (a) 4 mH.

What is the self inductance of a solenoid of length 10π cm, area of… | MHT CET 2026 (14 May, Shift 1)

Q6MHT CET 2026 · 14 MAY · SHIFT 1Easy

Self-Inductance & Energy

What is the self inductance of a solenoid of length $10\pi$ cm, area of cross-section $10^{-3}$ m ${}^{2}$ and total number of turns $10^{3}$ ? ( $\mu_0 = 4\pi \times 10^{-7}$ SI unit)

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Answer: (a)

$L = \dfrac{\mu_0 N^2 A}{l}$ with $l = 10\pi\text{ cm} = 0.1\pi\text{ m}$ .
$L = \dfrac{4\pi\times10^{-7}\times10^{6}\times10^{-3}}{0.1\pi}$
$L = \dfrac{4\times10^{-4}}{0.1} = 4\times10^{-3}\text{ H}$
So the answer is (a) 4 mH.

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Self-Inductance & Energy question from MHT CET 2026 (14 May, Shift 1)

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