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JEE Main 2021 (25 Jul, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2021 (25 Jul, Shift 1)

Q93JEE Main 2021 · 25 JUL · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

What should be the order of arrangement of de-Broglie wavelength of electron (λ\lambdae), an α\alpha-particle (λ\lambdaa) and proton (λ\lambdap) given that all have the same kinetic energy?

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Answer: (c)

  1. Same kinetic energy: λ=h2mK∝1m\lambda = \dfrac{h}{\sqrt{2mK}} \propto \dfrac{1}{\sqrt{m}}.
  2. me<mp<mα⇒λe>λp>λαm_e < m_p < m_\alpha \Rightarrow \lambda_e > \lambda_p > \lambda_\alpha
  3. So the answer is (c).
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