Student Login

Home›Chapters›Kinetic Theory of Gases PYQs›Law of Equipartition of Energy›Question 3

JEE Main 2021 (18 Mar, Shift 1) · Law of Equipartition of Energy

Law of Equipartition of Energy question from JEE Main 2021 (18 Mar, Shift 1)

Q3JEE Main 2021 · 18 MAR · SHIFT 1Easy

Law of Equipartition of Energy

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T? (kB is Boltzmann constant)

Show answer and solution

Answer: (a)

Equipartition: every degree of freedom gets equal average energy $\dfrac{1}{2}k_BT$ per molecule.
So the answer is (a) $\dfrac{1}{2}k_BT$ .

Report a mistake

More questions on Law of Equipartition of Energy

Given below are two statements: Statement I: In a diatomic molecule, the rotational…JEE Main 2021 (25 Feb, Shift 2)
A polyatomic gas with n degrees of freedom has a mean energy per molecule given byNEET 1989 (AIPMT)
Which statements are correct about degrees of freedom? (A) A molecule with n degrees of…JEE Main 2022 (27 Jul, Shift 2)
What will be the average value of energy for a monoatomic gas in thermal equilibrium at…JEE Main 2021 (22 Jul, Shift 2)