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MHT CET 2026 (13 Apr, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (13 Apr, Shift 2)

Q24MHT CET 2026 · 13 APR · SHIFT 2Medium

Thermal Radiation: Black Body, Stefan & Wien

What will be the ratio of rate of radiation of metal sphere at two different temperatures $T_1 = 527^\circ$ C and $T_2 = 127^\circ$ C

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Answer: (b)

Stefan's law: rate of radiation $\propto T^4$ (T in kelvin).
$T_1 = 800$ K, $T_2 = 400$ K
$\dfrac{P_1}{P_2} = \left(\dfrac{800}{400}\right)^4 = 16$
So the answer is (b) $16 : 1$ .

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