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NEET 1989 (AIPMT) · Motion Under Gravity

Motion Under Gravity question from NEET 1989 (AIPMT)

Q63NEET 1989 · AIPMTEasy

Motion Under Gravity

What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th seconds of journey?

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Answer: (b)

  1. Distance in the nnth second from rest: sn=g2(2n−1)s_n = \frac{g}{2}(2n-1)
  2. s4:s5=(2⋅4−1):(2⋅5−1)=7:9s_4 : s_5 = (2\cdot4-1) : (2\cdot5-1) = 7 : 9
  3. So the answer is (b) 7 : 9.
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