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JEE Main 2024 (27 Jan, Shift 2) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from JEE Main 2024 (27 Jan, Shift 2)

Q27JEE Main 2024 · 27 JAN · SHIFT 2Easy

Wheatstone Bridge & Metre Bridge

Wheatstone bridge principle is used to measure the specific resistance (S1)(S_1) of given wire, having length LL, radius rr. If XX is the resistance of wire, then specific resistance is; S1=X(πr2L)S_1 = X\left(\frac{\pi r^2}{L}\right). If the length of the wire gets doubled then the value of specific resistance will be:

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Answer: (d)

  1. Specific resistance (resistivity) is a property of the material, not of the wire's size.
  2. Doubling L doubles X, so S1=Xπr2LS_1 = X\frac{\pi r^2}{L} stays the same.
  3. So the answer is (d) S1S_1.
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