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MHT CET 2026 (19 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Easy

Thermal Radiation: Black Body, Stefan & Wien

When 170170 J of energy is incident on a surface of a body, 1717 J of energy is reflected by it. If the coefficient of absorption is 0.70.7, then the amount of energy transmitted will be

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Answer: (c)

  1. r=17170=0.1r = \dfrac{17}{170} = 0.1, a=0.7a = 0.7, so t=1−0.7−0.1=0.2t = 1 - 0.7 - 0.1 = 0.2
  2. Transmitted =0.2×170=34= 0.2\times170 = 34 J
  3. So the answer is (c) 34.0 J.
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