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MHT CET 2026 (13 May, Shift 1) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2026 (13 May, Shift 1)

Q10MHT CET 2026 · 13 MAY · SHIFT 1Medium

Splitting & Merging of Drops

When a big drop of water is formed from n small drops of water, the energy loss is 3E, where E is the energy of the big drop. If R is the radius of big drop and r is the radius of the smaller drop then number of smaller drops n is

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Answer: (d)

  1. E=4πR2TE = 4\pi R^2 T (big drop). Energy lost =4πT(nr2−R2)= 4\pi T(n r^2 - R^2).
  2. 4πT(nr2−R2)=3⋅4πR2T⇒nr2=4R24\pi T(n r^2 - R^2) = 3 \cdot 4\pi R^2 T \Rightarrow n r^2 = 4R^2
  3. n=4R2r2n = \frac{4R^2}{r^2}
  4. So the answer is (d).
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