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MHT CET 2026 (15 May, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2026 (15 May, Shift 2)

Q12MHT CET 2026 · 15 MAY · SHIFT 2Medium

Photoelectric Effect: Einstein's Equation

When a certain metal surface is illuminated with a light of wavelength λ\lambda, the stopping potential is VV. When the same surface is illuminated by light of wavelength 2λ2\lambda, the stopping potential is (V3)\left(\frac{V}{3}\right). The threshold wavelength for the surface is

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Answer: (c)

  1. hcλ−ϕ=eV\frac{hc}{\lambda} - \phi = eV and hc2λ−ϕ=eV3\frac{hc}{2\lambda} - \phi = \frac{eV}{3}
  2. Multiply the second by 3 and equate: 3hc2λ−3ϕ=hcλ−ϕ\frac{3hc}{2\lambda} - 3\phi = \frac{hc}{\lambda} - \phi
  3. hc2λ=2ϕ⇒ϕ=hc4λ\frac{hc}{2\lambda} = 2\phi \Rightarrow \phi = \frac{hc}{4\lambda}
  4. λ0=hcϕ=4λ\lambda_0 = \frac{hc}{\phi} = 4\lambda. So the answer is (c) 4λ4\lambda.
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