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JEE Main 2019 (12 Jan, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from JEE Main 2019 (12 Jan, Shift 2)

Q133JEE Main 2019 · 12 JAN · SHIFT 2Medium

Photoelectric Effect: Einstein's Equation

When a certain photosensitive surface is illuminated with monochromatic light of frequency v, the stopping potential for the current is –V0/2. When the surface is illuminated by monochromatic light of frequency v/2, the stopping potential is – V0. The threshold frequency for photoelectric emission is:

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Answer: (c)

Einstein: $h\nu = \phi + e|V_s|$
$h\nu - \phi = \frac{eV_0}{2}$ and $\frac{h\nu}{2} - \phi = eV_0$
$\frac{h\nu}{2} - \phi = 2(h\nu - \phi) \Rightarrow \phi = \frac{3h\nu}{2}$
$\nu_0 = \frac{3\nu}{2}$
So the answer is (c) $\frac{3\nu}{2}$ .

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