When a charge of 3 C is placed in uniform electric field, it experiences a force of 3000 N. Within this field, potential difference between two points separated by a distance of 1 cm is (a) 10 V (b) 90 V (c) 1000 V (d) 3000 V

Answer: (a). E = F/q = 3000/3 = 1000 N/C Uniform field: V = Ed = 1000 × 0.01 = 10 V So the answer is (a) 10 V.

When a charge of 3 C is placed in uniform electric field, it… | MHT CET 2023 (9 May, Shift 2)

Q61MHT CET 2023 · 9 MAY · SHIFT 2Easy

Electric Potential & Equipotentials

When a charge of $3\text{ C}$ is placed in uniform electric field, it experiences a force of $3000\text{ N}$ . Within this field, potential difference between two points separated by a distance of $1\text{ cm}$ is

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Answer: (a)

$E = \frac{F}{q} = \frac{3000}{3} = 1000\text{ N/C}$
Uniform field: $V = Ed = 1000 \times 0.01 = 10\text{ V}$
So the answer is (a) $10\text{ V}$ .

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